C语言编程，输入两个整数A，B，并输出其和值，可能很大_百度知道
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C语言编程，输入两个整数A，B，并输出其和值，可能很大
代码如下：#include &stdio.h&void main() { int a,b;printf(&请输入两个整数(a,b)：&);scanf(&%d,%d&,&a,&b); printf(&和：%d\n&,a+b); printf(&差：%d\n&,a-b);}
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for(;i&gt，B的每一位数然后转化为int型模拟加法运算.h&#include&string,j，那么A,num2[maxn],sum[maxn];int main(){} while(sum[i] == 0) i --.h&const int maxn = 10000;){printf(&0\n&quot,k;memset(s2;memset(s1;len1 = strlen(s1),0;&&s2[0]=='%s %s&;0&#39,&t)){while(t--){memset(num1;10;
sum[i] %= 10;while(~scanf(&%d&,sizeof(num1)),sizeof(num1));scanf(&quot，可以参考一下#include& i &= 0; i --,j++)num1[j] = s1[i]-'char s1[10000],s2[10000];int num1[maxn];0'for( i = 0; i& i++){sum[i] += num1[i] + num2[i];
sum[i+1] += sum[i]&#47,0,B可以无限大，应该算是一道经典大数题，一般运用char型数组接收A; len2 ? len1:len2;memset(sum,0,sizeof(sum));;for( i = len2 - 1, j = 0,'0'。下面这个代码是我的;for( i = len1 - 1;;int len = len1 &}int len1 ; i &= 0; i --,j++)
num2[j] = s2[i] - &#39,s1,s2);if(s1[0]==&#39,sum[i]),sizeof(s2)),j = 0;),i;len2 = strlen(s2),len2 ;=0; i--)printf(&%d&,sizeof(s1));memset(num2,'0'这种题不是普通的A+B，没有定义A,B的范围;0'0&#39
本回答被提问者采纳
unsigned long 的取值范围是0~如果还不够的话只能用数组自己定义加法运算了
可能很大的话，就用long int吧，实在不行，就unsigned long int
#include&stdio.h&main(){
int a[], b[];
int m,n,i,for(i=1;;i++);{printf(& please input
m and n:);scanf(&%d%d&,&a[i],&b[i]);printf(&add=%d&,a[i]+b[i]);}
楼主所发的这个代码应该是累加，而不是两个数相加。
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processed in 0.047 (s). 9 q(s)好多编程都没有错误，但就是无法输出结果，系统提示为应用程序错误，这是为什么？_百度知道
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好多编程都没有错误，但就是无法输出结果，系统提示为应用程序错误，这是为什么？
我有更好的答案
能把程序发上来看下吗？有的是编译器的问题，不要紧的，可能你的程序真的没问题。
#include&stdio.h&void main(){
int a,b,c,t;
printf(&Please input a,b,c=:&);
scanf(&%d,%d,%d&,a,b,c);
}printf(&%d\n&,a);}
#include&stdio.h&void main(){
int a,b,c,t;
printf(&Please input a,b,c=:&);
scanf(&%d,%d,%d&,a,b,c);
//这里没有取址符&，应该改为scanf(&%d,%d,%d&,&a,&b,&c);
}printf(&%d\n&,a);}
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所以运行时会出错。你可以单步执行程序，一般会有收获可能是你所使用的平台不兼容，也有可能是你自己的程序问题了，编译是没有error，但是在逻辑上有错误。这些是编译器检查不出来的。有时候写的程序在语法上没有错误
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回答问题，赢新手礼包单片机编程：a=3 b=‘a’结果显示b=97，怎么才能让结果显示为b=‘3’ 呀？谢谢啦！_百度知道
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单片机编程：a=3 b=‘a’结果显示b=97，怎么才能让结果显示为b=‘3’ 呀？谢谢啦！
我有更好的答案
，而不是把变量a的值赋给b;a&#39，让b=3，应该用一下语句实现：int a=3,b; b=a。要想把变量a的值赋给b你定义的b=‘a’，实际上是给b赋值字符&#39
采纳率：44%
a = 3;b = a + ‘0’;即可。
可以解释一下嘛？谢谢啦
楼主希望：b = ‘3’ ，即希望：b = 33H。而 '0' 即为 30H，加上 a 中的 3，即可满足楼主的要求。
本回答被网友采纳
是不是这样理解;
printf(&%d&，如果以整形输出就输出97，以字符型输出就是a；我理解你的意思是不是想把a的值赋给b，然后让b显示a的值;
b=a？如果用C语言编程，则如下：main(){unsigned
int a=3你要什么编程语言呀，实际上就是字符类型用整形输出的意思,你的程序b的赋值是字符，字符a对应的ASC码值是97
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回答问题，赢新手礼包}